June 2017 1HaskellADay 1Liners

• June 17th, 2017:
  f :: (a, [a]) -> [a] -> [a]
  f (c, w1) w2 = c:w1 ++ w2
  
  Define f points-free
• bazzargh @bazzargh (++).uncurry(:)
• Felt there must be a nicer way to exploit symmetry of mappend.uncurry(mappend.pure) but can't find it