Friday, July 7, 2017

June 2017 1HaskellADay 1Liners

  • June 17th, 2017:
    f :: (a, [a]) -> [a] -> [a]
    f (c, w1) w2 = c:w1 ++ w2

    Define f points-free
    • bazzargh @bazzargh (++).uncurry(:)
      • Felt there must be a nicer way to exploit symmetry of mappend.uncurry(mappend.pure) but can't find it

Monday, July 3, 2017

June 2017 1HaskellADay Problems and Solutions